Answer to Question #112967 in General Chemistry for Nicolas

Question #112967

If there are 0.0345 mols of HI in 47 mL of solution, what is its concentration? Also, what
is the pH?

Expert's answer

1.C(HI)=n(HI)/V=0.0345/0.047=0.734 mol/L

2.HI<=>H⁺+I^-;

pH=-lg[H+]=-lg(0.734)=0.134

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