Answer to Question #112970 in General Chemistry for Nicolas

Question #112970
If a 23.7 mL solution of H2SO4 has a concentration of 0.100 M, what is its pH? Also, how
many grams of H2SO4 are in the solution?
1
Expert's answer
2020-05-07T14:08:23-0400

Concentration is how many moles there are per unit volume, therefore, find the quantity of substance:


n=CV.n=CV.

The mass is the product of molar mass and n:


m=nM=CVM==0.1(23.7103)(12+32+164)=0.232 g.m=n\Mu=CV\Mu=\\=0.1(23.7\cdot10^{-3})(1\cdot2+32+16\cdot4)=0.232\text{ g}.


The pH is the negative decimal logarithm of hydrogen ion concentration in the solution. The sulphuric acid dissociates into two ions, both of the same and equal concentration of 0.100 M:


H2SO4=H++HSO4,pH=lg[H+]=lg[0.100]=1.\text{H}_2\text{SO}_4=\text{H}^++\text{HSO}_4^-, \\ \text{pH}=-\text{lg}[\text{H}^+]=-\text{lg}[0.100]=1.

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