Answer to Question #112963 in General Chemistry for Nicolas

Question

If there are 0.0345 mols of HI in 47 mL of solution, what is its concentration? Also, what
is the pH?

Answer 1

1.C(HI)=n(HI)/V=0.0345/0.047=0.734 mol/L

2.HI<=>H⁺+I^-;

pH=-lg[H⁺]=-lg(0.734)=0.134