"Q=cm\\Delta T" , Q - the amount of heat received by the substance during heating (J), c - The specific heat of the metal J/g*C, m - mass of substance (g), "\\Delta T" - the difference between the final and initial temperatures of the substance (oC).
"\\Delta T=T_2-T_1" = 20oC-14oC=6oC
Q=0,7279J/g*C*25g*6oC= 109,1850J
Answer:109,1850J
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