Question

How many joules can 25 g of a piece of metal absorbed when temperature increased from 14 Celsius to 20 Celsius? The specific heat of the metal is 0.7279 J/(g*C).

Answer 1

$Q=cm\Delta T$ , Q - the amount of heat received by the substance during heating (J), c - The specific heat of the metal J/g*C, m - mass of substance (g), $\Delta T$ - the difference between the final and initial temperatures of the substance (oC).

$\Delta T=T_2-T_1$ = 20oC-14oC=6oC

Q=0,7279J/g*C*25g*6oC= 109,1850J

Answer:109,1850J