Answer to Question #112668 in General Chemistry for Madi Sisson

Question

What mass of calcium chloride is required to make 500. mL of a 0.500M solution?

Answer 1

V = 0.5 L M = 0.5 mol/L

M = n/V n = M*V

n = 0.5*0.5 = 0.25 moles

1 mol CaCl₂ - 110.98 (g)

0.25 mol CaCl₂ - x (g)

x = 27.745 (g)

Answer: 27.74 g.