Answer to Question #112686 in General Chemistry for Beverlie

Question #112686
1. Calculate the solubility (in M) of cobalt(II) hydroxide, Co(OH)2(s) in H2O. Ksp = 3.60×10-16 at a specific temperature.
2. What is the pH of this solution of cobalt(II) hydroxide?
1
Expert's answer
2020-04-28T12:19:50-0400

Solution.

Co(OH)2    Co2Co(OH)_2 \iff Co^2 + +2OH+ 2OH^- ;

x 2x

Ksp=[Co2+][OH]2=x(2x)2=4x3=3.610K_sp = \lbrack Co^2+\rbrack\lbrack OH^-\rbrack^2 =x(2x)^2 = 4x^3 =3.6\sdot10-16;

x3=0.910x^3 = 0.9\sdot10 -16;

x=0.4510x = 0.45\sdot10 -5;

The molar solubility is 0.45\sdot 10-5 mol/L;

pH of Co(OH)2 pH=9.15;

Answer: The molar solubility is 0.45⋅ 10-5 mol/L; pH = 9.15.



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