Solution.
Co(OH)2 ⟺ Co2Co(OH)_2 \iff Co^2Co(OH)2⟺Co2 + +2OH−+ 2OH^-+2OH− ;
x 2x
Ksp=[Co2+][OH−]2=x(2x)2=4x3=3.6⋅10K_sp = \lbrack Co^2+\rbrack\lbrack OH^-\rbrack^2 =x(2x)^2 = 4x^3 =3.6\sdot10Ksp=[Co2+][OH−]2=x(2x)2=4x3=3.6⋅10-16;
x3=0.9⋅10x^3 = 0.9\sdot10x3=0.9⋅10 -16;
x=0.45⋅10x = 0.45\sdot10x=0.45⋅10 -5;
The molar solubility is 0.45⋅\sdot⋅ 10-5 mol/L;
pH of Co(OH)2 pH=9.15;
Answer: The molar solubility is 0.45⋅ 10-5 mol/L; pH = 9.15.
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