Solution.
"Co(OH)_2 \\iff Co^2" + "+ 2OH^-" ;
x 2x
"K_sp = \\lbrack Co^2+\\rbrack\\lbrack OH^-\\rbrack^2 =x(2x)^2 = 4x^3 =3.6\\sdot10"-16;
"x^3 = 0.9\\sdot10" -16;
"x = 0.45\\sdot10" -5;
The molar solubility is 0.45"\\sdot" 10-5 mol/L;
pH of Co(OH)2 pH=9.15;
Answer: The molar solubility is 0.45⋅ 10-5 mol/L; pH = 9.15.
Comments
Leave a comment