Answer to Question #111385 in General Chemistry for alexis

Question

Calculate the change in enthalpy for the following reaction, given that the standard enthalpy of formation for water is -285.5 kJ/mol, for oxygen is 0.0 kJ/mol, and for hydrogen peroxide is -187.8 kJ/mol. 2H₂O₍₎+ O₂₍₎ → 2H₂O₂₍₎

Answer 1

Change in enthalpy=heat content of products- heat content of reactants

$∆H=Hp-Hr$

∆H=-187.8kj/mol+285kj/mol=97.2kj/mol