Question

Given that chromium and lead electrodes are used to create a galvanic cell, what is E∘cell?

E∘Cr3+/CrE∘Pb2+/Pb=−0.744=−0.126

Answer 1

$3Pb(s)+2Cr^{3+}(aq)→3Pb^{2+}(aq)+2Cr(s)$

$E_o=0.744-0.126=0.618$