From the Mendeleev-Clapeyron equation we can express the pressure:
"p\u2022V = \\nu\u2022R\u2022T" "\\to" "p = (\\nu\u2022R\u2022T)\/V"
p = (1.16(mol)•8.31((N•m)/(mol•K))•295K)/7.73(m3) = 367.9 N/m2 = 0.03 atm
Answer: p = 0.03 atm
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