Answer to Question #109808 in General Chemistry for valerie

Question

What must the volume be for 1.95 mol of a gas at 8.33 atm and 283 K?

Answer 1

$P=8.33 atm;T=283 K;V=x;n=1.95 mole ;R=0.082057Latm mol^{-1}K^{-1}$

$PV=nRT$

$8.33×x=1.95×0.082057×283$

$x=5.436L$