Question

What is the molar mass of a noble gas in a 9.81 g sample that occupies a 3.00 L container at 100.0 kPa and 35.0˚C, What is the identity of the gas? *

Answer 1

some conversion which we are doing is 0^o C =273 K and 1 atm = 10⁵ Pa

Applying pV=nRT

$1\times3=n\times0.082\times308\\n=8.42$

hence the number of moles comes out to be 8.42

number of moles = $\frac{given \ mass }{molar \ mass}$

$8.42=\frac{9.81}{molar \ mass}\\molar \ mass = 1.17$