С(KCl)= n(KCl)/Vsolution;
n(KCl)= 0.048*0.75=0.036 mol;
Vsolution= 0.048+0.015=0.063 L
C(KCl)=0.036/0.063 = 0.57 M
Answer: the molarity of a kcl solution is 0.57 M
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