Solution.
The number of ways that N molecules can occupy B bulbs is W= BN
S=k"\\sdot" lnW, k=1.38"\\sdot" 10-23J/K.
a) 1000 molecules in bulb A
W=BN=11000=1;
S=( 1.38⋅ 10-23J/K )"\\sdot" ln(1)=0;
b)1000 molecules randomly distributed among bulbs A, B, and C
W=31000;
S=( ( 1.38⋅ 10-23J/K )⋅ ln(31000) =( 1.38⋅ 10-23J/K )⋅1000"\\sdot" ln(3)=1.5"\\sdot" 10-20J/K.
Answer:
a) W=1; S=0;
b) W=31000; S=1.5⋅ 10-20J/K.
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