Answer to Question #108537 in General Chemistry for meklit abby

Question

7.00 kg of calcium oxide was formed. What mass of calcium carbonate was heated?

Answer 1

Solution:

CaCO₃$\to$ CaO+Co₂ - the formula of reaction

m_CaCO3=n_CaCO3*M_CaCO3

n_CaCO3=n_CaO=m_CaO/M_CaO=7.00*10³g/(56g*mol^-1)=125mol

m_CaCO3=125mol*100g*mol^-1=12500g=12.50kg

Answer:

12.50kg of calcium carbonate was heated