"pK_a+pK_b=14\\\\pK_a=14-3.86=10.14"
pH of a weak acid solution is "-\\log[\\sqrt{CK_a}]=-\\frac12(\\log C+\\log K_a)=-\\frac12 \\log C+\\frac12pK_a=-\\frac12(-1.96)+5.07=6.05"
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment