pKa+pKb=14pKa=14−3.86=10.14pK_a+pK_b=14\\pK_a=14-3.86=10.14pKa+pKb=14pKa=14−3.86=10.14
pH of a weak acid solution is −log[CKa]=−12(logC+logKa)=−12logC+12pKa=−12(−1.96)+5.07=6.05-\log[\sqrt{CK_a}]=-\frac12(\log C+\log K_a)=-\frac12 \log C+\frac12pK_a=-\frac12(-1.96)+5.07=6.05−log[CKa]=−21(logC+logKa)=−21logC+21pKa=−21(−1.96)+5.07=6.05
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