HCl is a strong acid and dissociates completely to H+ and Cl-, therefore
pH = -lg[H+] = -lgC(HCl) = -lg0.00135 = 2.87
The equilibrium of dissociation is FCH2COOH = FCH2COO- + H+
the equilibrium constant is Ka = [H+]*[FCH2COO-]/[FCH2COOH]
C is initial concentration of the acid,
equilibrium concentrations are equal for [H+] = [FCH2COO-] = 10-2.87 = 0.00135 M,
equilibrium concentration of the acid is [FCH2COOH] = C - [H+] = C - 0.00135 M, hence:
Ka = [H+]2/(C-[H+])
10(-2.59) = 0.00257 = (0.00135)2/(C-0.00135),
C = (0.00135)2/0.00257 + 0.00135 = 0.00206 M
The initial concentration is 2.06*10-3 M
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