Co(HCl) = 11.6 M;
V1 = 10.0 mL;
V2 = 500.0 mL.
Solution:
Let's find a new concentration of hydrochloric acid (HCl) after dilution:
[HCl] = Co(HCl) * (V1 / V2) = 11.6 M * (10.0 mL / 500.0 mL) = 0.232 M.
HCl is a strong acid in aqueous media therefore it ionizes 100%.
HCl = H+ + Cl-
This means that
[H+] = [HCl] = 0.232 M.
[H+] = 0.232 M.
Answer: 0.232 M is the concentration of H+ ions in a solution of HCl.
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