At first let's find the amount of Magnesium Cyanide:
"\\nu = m\/M(Mg(CN)_2) = 7 (g)\/76 (g\/mol) = 0.092 (mol)"
Then find the volume of water:
"V = \\nu\/C = 0.092 (mol) \/0.500 (mol\/L) = 0.184 (L)"
Answer: 0.184 L of water needs to be added to 7.00 g of Magnesium Cyanide to make a 0.500M solution of Magnesium Cyanide
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