At first let's find the amount of Magnesium Cyanide:
ν=m/M(Mg(CN)2)=7(g)/76(g/mol)=0.092(mol)
Then find the volume of water:
V=ν/C=0.092(mol)/0.500(mol/L)=0.184(L)
Answer: 0.184 L of water needs to be added to 7.00 g of Magnesium Cyanide to make a 0.500M solution of Magnesium Cyanide
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