Answer to Question #106846 in General Chemistry for Mick

Question

e Theoretical moles of Sr3(PO4)2
determined from moles of Na3PO4·12H2O ?
3. Theoretical moles of Sr3(PO4)2 in Beaker I
determined from the limiting reagent ?
4. Theoretical yield of Sr3(PO4)2 in grams
# moles Sr3(PO4)2 x 452.80 grams ?

c. Formula of limiting reactant ?
d. Formula of excess reactant ?

Answer 1

Theoretical moles of Sr3(PO4)2 determined from moles of Na3PO4·12H2O: n (Sr3(PO4)2) = 1/2 n (Na3PO4·12H2O).

Theoretical moles of Sr3(PO4)2 in Beaker I

determined from the limiting reagent: 100% stoichiometric calculations!

c. limiting (One reactant (A) is chosen, and the balanced chemical equation is used to determine the amount of the other reactant (B) necessary to react with A. If the amount of B actually present exceeds the amount required, then B is in excess and A is the limiting reagent. If the amount of B present is less than required, then B is the limiting reagent.)

d. excess = total - react