"n=0.692 mol\\newline T=280K\\newline P=0.810bar=0.810*0.987=0.8atm\\newline R=0.0821\\hspace{0.1cm}\nlitre\\hspace{0.1cm} atm\\hspace{0.1cm} \/(K\\hspace{0.1cm} mol)\\newline\nPV=nRT\n\\newline\nV=19.88\\hspace{0.1cm}litre\\newline \nAnswer:19.88\\hspace{0.1cm}litre"
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