"x\\%(m\/v)" solution contains x grams of solute in 100 ml. of solution.
Thus, 250 ml of "8\\% (m\/v) NaOH" solution contains "8\/100*250=20 gms." of NaOH.
On adding, 750 ml. of water to this solution, volume of the solution becomes "250+750=1000ml."
Thus, the new diluted solution contains 20 gms. of NaOH in 1000ml. of solution.
Thus, concentration in %(m/v) "=20\/1000=2\/100=2\\%(m\/v)" . (Answer)
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