Question

What volume of 0.750M KCl solution is required to react exactly with 1325.0mL of 1.352 M Pb(NO3)2 solution

Answer 1

$2KCl +Pb(NO_3)_2\rightarrow PbCl_2+ 2KNO_3$

$1325 mL \times \frac{1L}{1000mL}= 1.325L$

moles of $(Pb(NO_3)_2)= 1.325 L \times \frac{1.352 mol}{1L}=1.791 moles$

$1.791 moles Pb(NO_3)_2\times \frac{2 mol KCl}{1 mole Pb(NO_3)_2}=3.583 mol KCl$

find volume of KCl solution:

$V=\frac{n}{c} = \frac{3.583 mol KCl}{0.750 \frac{mol}{L}}=4.777 L=4777 mL$