Acetylene combustion can be described by the following equation:
2C2H2 + 5O2 = 4CO2 + 2H2O
According to the reaction:
m(CO2) = [m(C2H2) × 4 × Mr(CO2)] / [2 × Mr(C2O2)
where m - mass, Mr - molecular weight.
From here:
m(CO2) = [1.56 kg × 4 × 44 g/mol] / [2 × 26 g/mol] = 5.28 kg
Answer: 5.28 kg
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