Answer to Question #105646 in General Chemistry for nuru fuseini

Question

4NaHCO3+9HCl= H2CO3+ NaCl
determine the number of moles of carbonic acid produced
which reactant limits the number of carbonic acid that can be made

Answer 1

NaHCO₃ + HCl = H ₂ CO ₃ + NaCl

According to a balanced reaction, the molar ratio in which NaHCO₃ and HCl react is = 1: 1.

Thus, when 4 moles of NaHCO₃ reacts with 9 moles of HCl, 5 moles of HCl remain unreacted.

Therefore, NaHCO₃ is a limiting reagent, and HCl is an excess of reagent.

Excess moles HCl = 9 - 4 = 5

Mole of formed H₂CO₃ = mole of reacting NaHCO₃ = 4