When the compound is dissolved it breaks into Mg2+,Cl−Mg^{2+}, Cl^-Mg2+,Cl− ions.
Let Molarity of the compound be x M.
Then molarity of the ions is as follows : Mg2+=xM,Cl−=2xMMg^{2+}=x M, Cl^-=2x MMg2+=xM,Cl−=2xM
Thus, amount of Mg present in 1000 ml is 24x24x24x gms. (since, atomic weight of Magnesium is 24 gm.)
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