Molar mass of glycerine = 92 g
moles of glycerine = 24.6/92 = 0.27
Molarity=molesvolume(in litres)=0.270.2665=\dfrac{moles}{volume(in \ litres)}=\dfrac{0.27}{0.2665}=volume(in litres)moles=0.26650.27=111
Osmotic pressure (π)=CRT(\pi)=CRT(π)=CRT where C is the molarity R is the gas constant and T is the temperature in kelvin
π=1∗0.082∗310=25.5atm\pi= 1*0.082*310=25.5 atmπ=1∗0.082∗310=25.5atm
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