Question

A sample of nitrogen at 20.0 °C has a volume of 891 mL at a pressure of 1,398 mmHg. To change the volume to 1,453 mL, what must be the new pressure?

Answer 1

pV=nRT

here temperature is constant and mole is also constant

so pV = constant

$p_1V_1=p_2V_2$

$891\times1398 =1435\times V_2$

$V_2=\dfrac{891\times1398}{1435}=868\ ml$