Question #103250

Derive integrated law for first order reactions

Expert's answer

Solution.

ABA\to B

d[B]dt=d[A]dt=k×[A]\frac{d[B]}{dt} = -\frac{d[A]}{dt} = k \times [A]

d[A][A]=kdt-\frac{d[A]}{[A]} = kdt

Integrate:

ln([A][A0])=k×t-ln(\frac{[A]}{[A0]}) = k \times t

ln([A0][A])=k×tln(\frac{[A0]}{[A]}) = k \times t

Answer:

ln([A0][A])=k×tln(\frac{[A0]}{[A]}) = k \times t


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