Answer to Question #102775 in General Chemistry for G

Question #102775
Calculate the number of milliliters of 0.639 M Ba(OH)2 required to precipitate all of the Pb2+ ions in 148 mL of 0.798 M Pb(NO3)2 solution as Pb(OH)2. The equation for the reaction is: Pb(NO3)2(aq) + Ba(OH)2(aq) Pb(OH)2(s) + Ba(NO3)2(aq) mL Ba(OH)2
1
Expert's answer
2020-02-11T05:38:39-0500

184,8 mL


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS