Answer to Question #102681 in General Chemistry for sakshi

Question #102681
Write down the molecular orbital configurations of N2 and NO. Calculate their bond orders. Which of these two is expected to have paramagnetic behavior?
1
Expert's answer
2020-02-17T07:06:33-0500

N2=(σ1s)2(σ1s)2(σ2s)2(σ2s)2(π2px)2(π2py)2(σ2pz)2(π2px)0(π2py)0(π2pz)0N_2= (\sigma_{1s})^2(\sigma^*_{1s})^2 ( σ _{2s} )^ 2 ( σ^ * _{2s} )^ 2 ( π _{2px} )^ 2 ( π _{2py} )^2 ( σ _{2pz} )^ 2 ( π *_ {2px} ) ^0 ( π^ *_{2py})^0(\pi^*_{2pz})^0


bond order=12×(104)=3bond \ order=\frac{1}{2}\times(10-4)=3


NO=N2=(σ1s)2(σ1s)2(σ2s)2(σ2s)2(π2px)2(π2py)2(σ2pz)1(π2px)0(π2py)0(π2pz)0NO=N_2=( \sigma_{1 s} )^2(\sigma^*_{1s})^2 ( σ _{2s} )^ 2 ( σ^ * _{2s} )^ 2 ( π _{2px} )^ 2 ( π _{2py} )^2 ( σ _{2pz} )^ 1 ( π *_ {2px} ) ^0 ( π^ *_{2py})^0(\pi^*_{2pz})^0


bond order =12×(94)=2.5\frac{1}{2}\times(9-4)=2.5

N2N_2 has not any unpaired electron so it is diamagnetic whereas NO has 1 unpaired electron so it is paramagnetic.


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