Question

A solution contains 6.30 x 10^2 g of oxalic acid, H2C2O4.2H2O, in 250 mL. What is the molarity of this solution

Answer 1

Molarity $M =moles/1000ml$

$Moles=630/90.03$ =6.998 moles

If 6.998 moles are in 250ml, then 1000ml will contain 27.992moles.

M=27.992/1000= 0.028M