ΔH=2ΔH1+ΔH2−ΔH3\Delta H=2\Delta H1 + \Delta H2 - \Delta H3ΔH=2ΔH1+ΔH2−ΔH3
ΔH=−182.5kJ\Delta H = -182.5 kJΔH=−182.5kJ