Let X* denote chromosome with allele for hemophilia and X denote the chromosome with normal allele.
The man's genotype is X*Y and his wife's genotype is X*X.
Their daughter could have either X*X or X*X* genotype. Thus, the probability for the daughter to be hemophiliac is 1/2.
The son could have genotype X*Y or XY. Thus, the probability to be hemophiliac is 1/2 as well.
Birth of each son is the independent event. Thus, the probability is 1/2 * 1/2 *1/2 =1/8.
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