In an arbitrary pedigree in which both parents are heterozygous normal for a trait (Aa), the outcome of the generation II will be for instance, two boys and two girls; one heterozygous (Aa) normal boy, one homozygous (AA) normal boy, one heterozygous (Aa) normal girl and one homozygous (aa) affected girl hence the type of inheritance will be more of sex-linked.
Therefore, the probability of 1,2,3,4 would be as follows.
1 (AA) will be 1/4
2 (Aa) will be 1/2
3 (Aa) will be 1/2
4 (aa) will be 1/4
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