A-achondroplasia
a-normal structure of the skeleton
B-syndactyly
b- normal structure of hand
A_bb- father had achondroplasia and normal structure
aaB_-mother had syndactyly and without achondroplasia
aabb-healthy daughter
If the daughter is healthy, her genotype is aabb, therefore the genotype of the father is Aabb, and the mother is aaBb, because the daughter receives one gene from the allelic pairs from the mother's organism, and the other from the father's.
P: ♂ Aabb x ♀aaBb
F1 AaBb -1/4= 25%-children with achondroplasia and syndactyly;
Aabb- 1/4= 25%-children with achondroplasia and normal structure of hand;
aaBb- 1/4= 25%- children with normal structure of the skeleton and syndactyly;
aabb - 1/4= 25%-healthy kids.
The probability of birth of the next healthy child constitute 25%.
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