If the frequency of two alleles in a gene pool is 90% A and 10%a, what is the
frequency of individuals in the population with the genotype Aa will be 18% (0,18)
p(A)=90%=0,9 in accordance with the Hardy-Weinberg equation:
q(a)=10%=0,1 the frequency of hereozygous pq individuals is 2pq
2pq-? 2pq=2*0,9*0,1=0,18 (18%)
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