According to Hardy-Weinberg equations:
p + q = 1
p2 + 2pq + q2 = 1
where p - frequency of the dominant allele, q - frequency of the recessive allele, p2 - frequency of homozygous dominant genotype, 2pq - frequency of heterozygous genotype, q2 - frequency of recessive genotype.
As 15% of the population carries a copy of the recessive allele (q=0.15), 100% - 15% = 85% of the population carries a copy of the dominant allele (p=0.85).
As a result, the predicted frequency of individuals in the population that express the dominant phenotype equals p2 + 2pq = 0.852 + 2 × 0.85 × 0.15 = 0.9775 = 0.98
The predicted frequency of individuals in the population that express the recessive phenotype equals q2 = 0.152 = 0.0225 = 0.02.
Answer: 0.98 and 0.02
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