Answer to Question #243911 in Quantum Mechanics for Ghadeer

Question #243911
Suppose that the car is stopped from 27m/s within right after the collision and the driver 75kg didn’t push the brake.Seatbelt is non-stretchable and produces a constant force to stop the driver in 10 cm . Calculate the acceleration of the driver and the force that the seatbelt acts on the driver for above two conditions.
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Expert's answer
2021-09-28T16:54:23-0400

E=mv22,E=\frac{mv^2}2,

A=Fs,A=Fs,

E=A,E=A,

F=mv22s=273 kN,F=\frac{mv^2}{2s}=273~kN,

a=Fm=3645 ms2.a=\frac Fm=3645~\frac{m}{s^2}.


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