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Solve (p + q)(px + qy) = 1, using Charpit’s method.
Solve:
x².d²y/dx² -x.dy/dx +y=ln x
Transform the general equation of circle : x2 + y2 + 4x - 2y -11 =0 to its standard form or center-radius form. After transforming , identify the center and the radius then sketch the graph in the Cartesian coordinate plane .
Calculate the new boiling point of a solution containing 5.27 g of sucrose (C12H22O11) and 45 g of water
In a mass transfer apparatus operating at 1 atm. the individual
mass transfer coefficients have the following values
kx = 22 kmol/ m2
. h (Δx = 1)
ky = 1.07 kmol/ m2
. h (Δy = 1)
The equilibrium compositions of the gaseous and liquid phases are
characterized by Henry’s law:
p = 0.08 x 106
x, mm of Hg
(i) Determine the overall mass transfer coefficients Kx and Ky.
(ii) Determine the ratio of diffusional resistances of the liquid and gaseous
phases.
Hydrochloric acid (A) diffuses through a thin film of water (B)
4 mm thick at 283 K and 1 atm ressure. The concentration of HCl at point 1 on
one boundary of the film is 12 wt % with density of 1060.7 kg/m3
and on the
other boundary, at point 2, is 4 wt % of density1020.15 kg/m3
. The diffusivity
of HCl in water at 293 K and 1.5 atm is 2.5 x 10-9 m
2
/s. Calculate the flux of
HCl considering water to be stagnant.
Ammonia is being absorbed from air-ammonia mixture by
sulphuric acid solution. The concentration of ammonia 2.5 cm from the acid
surface is 40% by volume and concentration at the acid surface is zero. The
total pressure of the system is 400 mm Hg and the temperature is 288 K. The
value of diffusivity is 1.73 X 10-5 m2
/s at 293 K and 1 atm. Calculate the
following:
(i) Rate of absorption of ammonia across 0.045 m2
of acid surface.
(ii) Concentration of ammonia 1.25 cm from the acid surface
Supposed the disposable income ranges from 1,110,000 to 1,290,000 and it increases by 30,000 per year. Mpc = .80
When disposable income is 1,000,000 what is the level of consumption is equal to?
int i,l,p=0,j; char c; String s,w="",r="";
System.out.println("Enter a String");
s = sc.nextLine(); s = s.trim()+" "; l = s.length();
for (i=0;i<l;i++) {
c = s.charAt(i);
if (c != 32)
w = w + c;
else { p++;
for (j=w.length()-1;j>=0;j--) {
c = w.charAt(j); r = r + c;
} if (w.compareToIgnoreCase(r) == 0 && r.length() > 1)
System.out.println(w+"\t"+p);
w = ""; r = "";
}
if (i == l-1) {
p++;
for (j=w.length()-1;j>=0;j--) {
c = w.charAt(j);
r = r + c;
}
if (w.compareToIgnoreCase(r) == 0 && r.length() > 1)
System.out.println(w+"\t"+p); }}}}
Q. Above coding will display palindrome words along with its position that is where it is present in the String. Add a statement to above coding so that it will display ''No palindrome words found" if there is not a single palindrome word present in the entered String.
A proton and an electron are initially at rest at a distance of 9×10-¹⁰m. What will be their initial acceleration due to the electric force that they exert on each other?
#339914 on Dec 2023