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Naturally occurring lithium has 7.45% 6Li and 92.6% 7Li.what is the RAM of the lithium?

 For the experiment Taru has N buckets (numbered from 1,2,3..N) which all are initially empty. She has M number of queries. Each query represents an integer that is of 4 types. Query 1: Fill all the buckets with water •Query 2: Empre even valued buckets (2, 4, 6 N) Query 3: Empty all odd number buckets (1, 3, 5, N). •Query 4: Empty all the buckets (1,2,3. N). You have to return the number of buckets that are filled after performing M queries,using fillbucket function


F ind aba -1 w here (i) a = (5 , 7 , 9) , b = (1 , 2, 3) (ii) a = (1 , 2,5)(3 , 4) , b = (1 , 4 , 5)


Given the data 6, 9, 12, 15, 16, 19, 22. Construct a sampling distribution of the sample mean without replacement and repetition by selecting 2 samples at a time.


given the following code what is the value of cities[3]

String cities[] = new String[5];

  cities[0] = "North bay";

  cities[1] = "Windsor";

  cities[2] = "Kitchener";

  cities[3] = "Kingston";

  cities[4] = "Ottawa";


Determine the present value of a loan if R12 000 is due in ve years' time, at a simple dis


ount rate of 15%


per annum.


[1℄ R12 656,25


[2℄ R12 972,97


[3℄ R13 125,00


[4℄ R13 664,28

Prove that \sum_{i=0}^{n} 2^{i} = 2^{n + 1} - 1 Use mathematical induction for this proof and discuss/explain each step.


Given the following How many elements are in the array die3

 int die1[] = {1,0,2,0,3,1};

 int die2[] = {2,1,0,4,0,3};

 int die3[] = {3,0,3,0,3,4};

 int die4[] = {2,0,1,0,3,5};

 int die5[] = {1,0,2,0,3,4};

 int die6[] = {4,0,1,2,3,2};

  int dice[][] = {die1,die2,die3,die4,die5,die6};


How to execute this using vector



#include <cmath>


#include <iomanip>


#include <iostream>



using namespace std;



int fibo(int n);



int main() {



string header = " Index Fibonacci number Fibonacci quotient Deviation";



double lim = (1.0 + sqrt(5.0)) / 2.0;



int fib_sequence[21];




for (short i = 0; i < 21; i++) {


fib_sequence[i] = fibo(i);


}



cout << header << endl;



for (short i = 0; i < 20; i++) {



double q = (double)fib_sequence[i + 1] / (double)fib_sequence[i];



cout << setw(5) << i << setw(15) << fib_sequence[i] << setw(20) << fixed


<< setprecision(10) << q << setw(20) << scientific << setprecision(3)


<< lim - q << endl;


}



return 0;


}


int fibo(int n) {


if (n <= 1)


return n;



return fibo(n - 1) + fibo(n - 2);


}

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