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Given a four digit number N as input write a program to print first and last digit of the number

Quite tiring to write those things separated by commas and a single space, isn't it?

Then let's try coding it instead

Five lines containing a string on each.

A single line containing all the strings separated by a comma and a space.


Have you ever answered a test question that tells you to enumerate a series of things, but the answer must be in a sentence? Quite tiring to write those things separated by commas and a single space, isn't it?

Then let's try coding it instead


Given a list of integers, write a program to print the count of all possible unique combinations of numbers whose sum is equal to k.



Input:



The first line of Input will contain space-separated Integer.



The second line of Input will contain an 8nteger,denoting K.




Sample Input:



2 4 6 1 3




Output:



3

  1. In the code editor, you are provided with a main() function that asks the user for two integers and calls the slowDisplay() function.
  2. This slowDisplay() function is a recursive function which should perform the functionality explained in the problem description above.
  3. This function is only partially implemented as it lacks a base case. Your task is to add the base case needed by this recursive function.

Example:

Starting num = 2

Next num = 3

It should then print 3 4 5


Given code:

#include <iostream>

using namespace std;


void slowDisplay(int, int);


int main(void) {

  int start, nextCount;


  cout << "Enter starting integer: ";

  cin >> start;


  cout << "Enter how many next integers: ";

  cin >> nextCount;


  slowDisplay(start + 1, nextCount);


  return 0;

}


void slowDisplay(int start, int nextCount) {

  // TODO: Add the base case here

  if(start == 0) {

    

    cout << start << " ";

    slowDisplay(start + 1, nextCount - 1);

  }

}



  1. In the code editor, you are provided with a main() function that asks the user for a string and passes this string and the size of this string to a function call of the function, preserveString().
  2. This preserveString() function has already been partially implemented. Your only task is to add the recursive case of this function.

To do: Print the string repeatedly, each time it prints the string, exclude the last letter until only 1 letter is left.


Given code:

#include <iostream>

#include <cstring>

using namespace std;


#define STR_MAX_SIZE 100


void preserveString(char*, int);


int main(void) {

  char str[STR_MAX_SIZE];


  cout << "Enter string: ";

  fgets(str, STR_MAX_SIZE, stdin);


  preserveString(str, strlen(str));


  return 0;

}


void preserveString(char *str, int size) {

  if(size > 0) {

    for(int i = 0; i < size - 1; i++) {

      cout << str[i];

    }

    cout << endl;


    // TODO: Add the recursive case of the function here

  }

}



#include <iostream>




ung namespace std;




#include <string> class snident




string name="DefaultName":




string birthyear= "9999":




Your Code Here




int main(){




sident $1;




student $2("Geoffrey Hinton"); student $3("Yann LeCun", "1960");




s1.print_info(); print_info();




$3.print_info():




$2.change year(1947");




s1 change_name("YourName");




s1.change year("YourBirth Year>");




$2.print info(); $1.print_info();




return 0;




Complete the student class so the main function above produces the following output:




Name: DefaultName, Birth Year: 9999




Name: Geoffrey Hinton, Birth Year: 9999.




Name: Yann LeCun, Birth Year: 1960 Name: Geoffrey Hinton, Birth Year: 1947.




Name: YourName, Birth Year: <Your Birth Year>

• Using Php Script write a program that will compute the students average



• The user will input the following:



 Name



 Math



 Science



 English



• If the average is equal and above 75, it will display “Congratulations. You passed the semester” otherwise “You failed the semester.”


getsize return the size of collection


getsize return the size of collection


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