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Odd-Even-inator

by CodeChum Admin

My friends are geeking out with this new device I invented. It checks if a number is even or odd! 🤯


Do you want to try it out?


Instructions:

  1. In the code editor, you are provided with a function that checks whether a number is even or odd.
  2. Your task is to ask the user for the number of integer, n, they want to input and then the actual n number values. For each of the number, check whether it is even or odd using the function provided for you.
  3. Make sure to print the correct, required message.

Input


1. Integer n

2. N integer values

Output


Enter·n:·5
Enter·value·#1:·3
3·is·odd
Enter·value·#2:·6
6·is·even
Enter·value·#3:·4
4·is·even
Enter·value·#4:·1
1·is·odd
Enter·value·#5:·3
3·is·odd

 Before and After

by CodeChum Admin

The only constant thing in the world is change. That’s why we need to call the toupper() function to change what we already have into a better version.


Instructions:

  1. Your task is to ask the user for a character input.
  2. Then, include the cctype built-in library and call the toupper() function. In case you do not know what this function is, this function has the following definition:
  3. Return type - int
  4. Name - toupper
  5. Parameter - one integer which represents the ASCII of a character
  6. Description - returns the ASCII of the uppercase equivalent of the character passed
  7. Extra note - even though it's function definition in the C++ Programming Language Documentation is int toupper(int ch), you can just pass a normal char variable instead and this will just be automatically typecasted/converted to its integer equivalent.
  8. Once you get the uppercase equivalent, print this out.

Input


1. Letter to be updated

Output


Enter·a·small·letter:·a
Uppercase·=·A




 Leap Year Detector

by CodeChum Admin

Let’s try to find out whether a year has 365 or 366 days. To do this, we need to create a leap year detector!


Conditions for a leap year:

1.) year must be divisible by 4 and not divisible by 100

2.) If year is divisible by 100, it must be divisible by 400 for it to be a leap year.


Instructions:

  1. You are provided with the isLeapYear() function which is already declared and defined for you.
  2. Your task is to ask the user for a year and then call the isLeapYear function to check whether the year is a leap year or not.

Input


1. Year to be checked

Output

If a certain year is a leap year, print "<INSERT_YEAR_HERE> is a leap year"

Otherwise, print "<INSERT_YEAR_HERE> is not a leap year"

Enter·year:·2020
2020·is·a·leap·year




Preserving the Gene Pool


by CodeChum Admin



In order to make sure that the future generations will grow into great beings, we must make sure that the gene pool consists of the best genes. In order to do that, we must compare genes from each other and find out which one is the best!





Instructions:



In the code editor, you are provided with a main() function that asks the user for 4 integer inputs and passes these to the getBest() function call.


Your task is to declare and define this getBest() function which has the following details:


Return type - int


Name - getBest


Parameters - 4 integers


Description - returns the highest integer passed


DO NOT EDIT ANYTHING IN THE MAIN


Input



1. First integer



2. Second integer



3. Third integer



4. Fourth integer



Output



Enter·a:·10


Enter·b:·3


Enter·c:·15


Enter·d:·14


Highest·integer·=·15


Pairing Up


by CodeChum Admin



You’re tasked with pairing up people with each other but you need to figure out how well both of them work together. In order to find out how effective each pair is, you need to create a program that adds both of their values and returns their sum.





Instructions:



In the code editor, you are provided with a main() function that asks the user for two integer inputs, passes these to a function called, getSum(), and then prints the returned value.


Your task is to declare and define the getSum() function which has the following details:


Return type - int


Name - getSum


Parameters - 2 integers


Description - adds the passed integers and returns their sum


DO NOT EDIT ANYTHING IN THE MAIN


Input



1. First integer



2. Second integer



Output



Enter·first·number:·24


Enter·second·number:·21


Sum·=·45

Survival of the Biggest (JAVA)

by CodeChum Admin

Looping a number and taking away each digit of it is so much fun, but I wanted to try out a much more complex task: getting the largest digit among them all.

Think you can handle the job?


Instructions:

  1. Input a non-zero positive integer.
  2. Using the same concept as the previous problem, figure out how to separate the digits of a number and determine which of the digits is the largest one, using a while. Afterwards, print the largest digit.
  3. Tip #1: Create another variable that will hold the largest digit. Initial its value to a negative integer, like -1, outside the loop.
  4. Tip #2: Everytime you get the rightmost digit, check if it is greater than the current largest digit. If it is, set it as the new largest digit.

Input

A line containing an integer.

214

Output

A line containing an integer.

4

Problem:

Compute and display the output of the Area (A) of a rectangle, based on

inputted value for length (L) and the width (W).

Formula: A = L * W


Create a short program that will print 123467.89 as currency using NumberFormat.



Sample Output:


------------------------------------------------------------------


I have ₱1,234,567.89 in my bank account.

Create a short program that will generate a random number from 0 to 100 while using Math.random and Math.round command.


Submit your answers by attaching a screenshot of your program's source code and 3 screenshot of it's output.



Write a program that declares and initializes an array of 7 integers. The program uses these static methods to perform different operations on the array:

void printArray(int[] arr) – takes the array as parameter and prints the array in horizontal order

int sumOfArray(int[] arr) – takes the array as parameter and returns the sum of the array

int getHighest(int[] arr) – takes the array as parameter and returns the highest value in the array

int resetArray(int[] arr) – takes the array as parameter and resets the value of each element to 0


Sample output:

Here’s the array: 

3 1 3 2 1 9 1

Sum: 20

Highest: 9

Here’s the array: 

0 0 0 0 0 0 0




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