Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Search & Filtering

#Loop through the prices in levelsList.
#During each loop:
#-Create a variable called priceLevelLabel consisting of the text 'Price Level: 'followed
# by the price.
#-Add priceLevelLabel and the price as two separate items to a new list (the sub-List).
#-Append the sub-List to displayList.
for price in self.levelsList:

class List

{

  public:

  int item;

  int pos=0;

  List* nextNode;

};

void Insert_Element(List** head, char data)

{

  List* node = new List();

  node->item = data;

  node->nextNode = (*head); 

  (*head) = node; 

}


 void PrinList(List *node){

  List *temp = node;

  while(temp !=NULL){

  cout<<temp->item<<" ";

  node->pos ++;

  temp = temp->nextNode;

}

cout<<"\n";

 }


int Length(List *node){

return node->pos;

}


bool is_Empty(List *node){

if(node->pos==0){

return true;

}

else {

return false;

}

}


void Copy_List(List*node, List *list){

List * temp = node;

while(temp !=NULL){

int data = temp->item;

Insert_Element(&list, data);

temp = temp->nextNode;

}

cout<<"The copied list is:\n";

PrinList(list);

}


note:

Create constructor(default,parameterized and copy) and a manu of test the functions.



# Create displayList

    displayList = []

# Loop through the prices in levelsList.

 # During each loop:

 # - Create a variable called priceLevelLabel consisting of the text 'Price Level:  '

followed by the price.     

# - Add priceLevelLabel and the price as two separate items to a new list (the sub-List).     

# - Append the sub-List to displayList. for price in self.levelsList:

 . . .

 # Create a variable called previousPriceLabel consisting of the text 'Previous Price: ' followed 

# by previousPrice. # Add previousPriceLabel and previousPrice as two separate items to a new list (the sub-List).  # Append the sub-List to displayList.

. . .

# replace ellipsis with applicable cod


#During the first loop of this method, previousPrice will still be 0 here,
#because it was set to currentPrice above, which also was 0 before we updated
#it above via getBitMexPrice().
#So, when we reach this point during the first loop, previousPrice will be 0
#while currentPrice would have just been updated via getBitMexPrice().
#We don't want to create the impression that the price shot up from 0 to
#currentPrice.
#ThereFore, if previousPrice == 0.0, it must be set equal to currentPrice here.

Why do we care that the expressions are equivalent? (5) 2.3.3 How can we determine that the expressions are equivalent? 



An e-commerce company is planning to give a special discount on all it's products to its customers for the Christmas holidays.

Input:
7
9-13 8-7 18-10
18
Output:
2

Given the following declarations, what is the result of each of the assignments?

   int w = 5, y = 9, z = 2;

a. z = w * y;

b. z += y;

c. y /= z;

d. y %= z;

e. y += y++;

f. y += --y;



Prepare a c++ program

 board[4][3] = { {2,3,1},{15,25,13},{20,4,7},{11,18,14}};

              

                                    


 Given the following declarations, what is the result of each of each output?

   char a = 'a', b = 'B';

   char c = ' ', d;

   string s = "This is fun.";

   int e;

System.out.println a. ("a = " + a); b.("a = " + 'a'); c.(a + b);

d. (s);

e. (s.length());


Prepare a c++ program of the two-dimensional array of the sample run below:


Sample Run:

              [0]         [1]        [2]     [3]        [4]        [5]

  [0] 

  [1] 

  [2] 

  [3] 

  [4] 

  [5]                    9.5

  [6] 

  [7] 

  [8] 

  [9] 

  [10] 

  [11] 


LATEST TUTORIALS
APPROVED BY CLIENTS