Answer to Question #347476 in Python for R43

Question

Find the unique alphabet in a string and find the index of that character If multiple unique chars are in a given string, then return the first unique character index,if there is no unique alphabet then print -1

Note: index format is 1

For example :

given string: statistics

Given string having a, c as unique chars

The first unique char is a

character an index in the given string is 3 (index is 1 format)

output: 3

For example : "helloram"

unique chars = [h,e,o,r,a,m]

first one out of them is "h

Answer 1

N = input("Enter word: ")


def first_unique_character(str1):
    char_order = []
    ctr = {}
    for c in str1:
        if c in ctr:
            ctr[c] += 1
        else:
            ctr[c] = 1
            char_order.append(c)

    for c in char_order:
        if ctr[c] == 1:
            return c
    return char_order


letter = list(first_unique_character(N))
if len(letter) == 1:
    print(N.find(letter[0]) + 1)
else:
    print('-1')