Answer to Question #318580 in Python for Cristelle Maddela

Question

Develop a Python application which will accept n non-negative integers and will display the DIVISORS of each number then will determine the COMMON DIVISORS of the input integers.

Sample Output:

How many numbers? 4

Input Number 1: 10

Input Number 2: 50

Input Number 3: 15

Input Number 4: 20

Divisors

10: 1 2 5 10

50: 1 2 5 25 10 50

15: 1 3 5 15

20: 1 2 5 10 20

COMMON Divisors is/are: 1 5

I need the code to have an output stated above.

Answer 1

n = int(input("How many numbers?: "))
numbers = [0] * n
divisors = []
common = []
for i in range(n):
    numbers[i] = int(input(f"Input Number {i+1}: "))
    divisors.append([])
    for j in range(1, numbers[i]+1):
        if (numbers[i] % j) == 0:
            divisors[i].append(j)
print()
print("Divisors")
for i in range(n):
    print(f"{numbers[i]}: ", end="")
    for j in range(len(divisors[i])):
        print(f"{divisors[i][j]} ", end="")
    print()
print()
print("COMMON Divisors is/are: ", end="")
for i in range(len(divisors[0])):
    cnt = 0
    for j in range(1, n):
        for k in range(len(divisors[j])):
            if divisors[j][k] == divisors[0][i]:
                cnt += 1
                break
    if cnt == (n-1):
        common.append(divisors[0][i])
for i in range(len(common)):
    print(common[i], end=" ")