Answer to Question #310983 in Python for Siva

Question

you are given an m*n matrix.write a program to compute the perimeter of the matrix and print the result.perimeter of a matrix is defined as the sum of all elements of the four edges of the matrix

m = no of rows

n = no of columns

Ex: [1 2 3 4

5 6 7 8

9 10 11 12]

Perimeter : 1+2+3+4+8+12+11+10+9+5 = 65

Note: take input from the user.

Answer 1

matrix=[]
print('Enter no of rows: ', end='')
m = int(input())
print('Enter no of columns: ', end='')
n = int(input())
print('Enter matrix (sep. space):')
for i in range(m):
    a = input().split()
    matrix.append([])    
    for j in range(n):
        matrix[i].append(int(a[j]))
sum = 0
print('Perimeter: ', end='')
for j in range(0, n):
   print(f'{matrix[0][j]}', end='')
   if j < n:
      print('+', end='')   
   sum = sum + matrix[0][j]
for i in range(1, m-1):
   print(f'{matrix[i][n-1]}', end='')
   if i < m-1:
      print('+', end='')
   sum = sum + matrix[i][n-1]
for j in range(n-1, -1, -1):
   print(f'{matrix[m-1][j]}', end='')
   if j > -1:
      print('+', end='')   
   sum = sum + matrix[m-1][j]
for i in range(m-2, 0, -1):
   print(f'{matrix[i][0]}', end='')
   if i > 1:
      print('+', end='')
   sum = sum + matrix[i][0]   
print(f'= {sum}')