Answer to Question #303735 in Python for petals

Question

Write a program to solve a quadratic equation ax² + bx + c = 0. Always check if the discriminant (D)

> 0, then the equations has two roots

= 0, then the equation has one root (two equal roots)

< 0, the equation has no real roots 

where    D = square root of b² - 4ac

Answer 1

a = int(input())
b = int(input())
c = int(input())
# a^2 + bx + c = 0
d = b ** 2 - 4 * a * c
if d > 0:
  print('x1 =', (-b-sqrt(d)) / (2*a))
  print('x2 =', (-b+sqrt(d)) / (2*a))
elif d == 0:
  print('x1 = x2 =', -b / (2*a))
else:
  print('No roots')