Answer to Question #303089 in Python for Cristelle Maddela

Question

Create a Python script which will accept a positive integer and will determine the input number if PERFECT, ABUNDANT, DEFICIENT.

PERFECT – if the sum of the divisors of the number except the number itself is 

equal to the number.

E.g. 6 = 1, 2, 3, 6 1 + 2+ 3 = 6

ABUNDANT – if the sum of the divisors of the number except the number itself 

is greater than the number.

E.g. 12 = 1, 2, 3, 4, 6, 12 1 + 2 + 3 + 4 + 6 = 16

DEFICIENT – if the sum of the divisors of the number except the number itself is 

less than the number.

E.g. 10 = 1, 2, 5, 10 1 + 2 + 5 = 8

Sample Output:

Input a Positive Integer : 20

20 is ABUNDANT!

I need the code to have an output stated above.

Answer 1

def type_of_num(num):
    factors = []
    for i in range(1, num + 1):
       if num % i == 0:
           if i != num:
               factors.append(i)
    if sum(factors) == num:
        type_num = "Perfect"
    elif sum(factors) > num:
        type_num = "Abundant"
    else:
        type_num = "Deficient"
    return type_num, factors

print(type_of_num(32))