Answer to Question #302439 in Python for sai

Question

Find perimeter of a matrix without using numpy

Input1:

1 2 3

4 5 6

7 8 9

Output: 40

Input2:

1 2 3 4

5 6 7 8

9 10 11 12

13 14 15 16

Output: 102

Answer 1

#!usr/bin/python
import numpy as np

# read matrix
mtx = np.arange(1, 10).reshape(3, 3)
print(mtx)

# calc size of the matrix
n = len(mtx);

# calc perimeter of the matrix
perimeter = sum(mtx[0]) + sum(mtx[n-1])
mtx.transpose()
perimeter = perimeter + sum(mtx[0]) + sum(mtx[n-1])
perimeter = perimeter - mtx[0][0] - mtx[0][n-1] - mtx[n-1][0] - mtx[n-1][n-1]

# print the answer
print(perimeter)