Answer to Question #298186 in Python for Kaavya

Question

Rotate matrix rings

Given a matrix of order M*N and a value K, write a program to rotate each ring of the matrix clockwise by K elements. If in any ring has less than or equal to K elements, then don't rotate that ring.

Input:

The first line of input will be two space separated integers, denoting the M and N. The next M lines will contain N space separated integers. The next line will contain an integer, denoting K

Output:

The output should be M*N matrix by K elements.

Sample input:

3 4

1 2 3 4

10 11 12 5

9 8 7 6

2

Sample output:

9 10 1 2

8 11 12 3

7 6 5 4

Answer 1

def replace_arr(arr, k):


	return arr[-k:] + arr[:-k]


def rotete_rings(matrix, r):


	tmp = []
	k = 0
	l = 0
	m = len(matrix)
	n = len(matrix[0])
	while (((n - k) > 0) and ((m - l) > 0)):
		for i in range(k,n):
			tmp.append(matrix[k][i])
		for j in range(l+1,m):
			tmp.append(matrix[j][n-1])
		for i in range(n-2,k-1,-1):
			tmp.append(matrix[m-1][i])
		for j in range(m-2,l,-1):
			tmp.append(matrix[j][k])
		if len(tmp) <= r:
			break
		tmp = replace_arr(tmp,r)
		c = 0
		for i in range(k,n):
			matrix[k][i] = tmp[c]
			c += 1
		for j in range(l+1,m):
			matrix[j][n-1] = tmp[c]
			c += 1
		for i in range(n-2,k-1,-1):
			matrix[m-1][i] = tmp[c]
			c += 1
		for j in range(m-2,l,-1):
			matrix[j][k] = tmp[c]
			c += 1		
		tmp = []
		k += 1
		l += 1
		m -= 1
		n -= 1
	return matrix






m, n = input().split()
m, n = int(m), int(n)
matrix = [[int(i) for i in input().split()] for _ in range(m)]
k = int(input())


rotated_matr = rotete_rings(matrix, k)


for row in rotated_matr:
	print(*row)